Single Variable CalculusIntegral FormulaIntegral with ax²+bx+cOn this pageIntegral with ax2+bx+cax^2+bx+cax2+bx+c 29 ∫1ax2+bx+c dx={24ac−b2arctan2ax+b4ac−b2+C(4ac>b2)1b2−4acln∣2ax+b−b2−4ac2ax+b+b2−4ac∣+C(4ac<b2)\int \frac{1}{ax^2+bx+c}\ \mathrm{d}x= \left\{\begin{aligned} &\frac{2}{\sqrt{4ac-b^2}}\arctan{\frac{2ax+b}{\sqrt{4ac-b^2}}}+C \left(4ac>{b^2}\right)\\ &\frac{1}{\sqrt{b^2-4ac}}\ln {\left|\frac{2ax+b-\sqrt{b^2-4ac}}{2ax+b+\sqrt{b^2-4ac}}\right|}+C\left(4ac<{b^2}\right) \end{aligned} \right.∫ax2+bx+c1 dx=⎩⎨⎧4ac−b22arctan4ac−b22ax+b+C(4ac>b2)b2−4ac1ln2ax+b+b2−4ac2ax+b−b2−4ac+C(4ac<b2) Derivation 30 ∫xax2+bx+c dx=12aln∣ax2+bx+c∣−b2a∫1ax2+bx+c dx\int \frac{x}{ax^2+bx+c}\ \mathrm{d}x=\frac{1}{2a}\ln{\left|ax^2+bx+c\right|}-\frac{b}{2a}\int \frac{1}{ax^2+bx+c}\ \mathrm{d}x∫ax2+bx+cx dx=2a1lnax2+bx+c−2ab∫ax2+bx+c1 dx Derivation